Soil Mechanics Laboratory · Geotechnical Engineering

Direct Shear Calculator — Cohesion c and Angle φ

The direct shear test in a shear box (BS 1377-7 + BS EN ISO 17892-10) provides the Mohr-Coulomb shear strength parameters: cohesion c and friction angle φ. This calculator fits the linear envelope τ = c + σ·tan φ by least-squares regression to the (σn, τ) pairs measured in the laboratory, typically 3-4 points with different normal pressures. It also calculates residual (post-peak) parameters useful for slope stability analysis with prior movements and large deformation diagnostics.

What is it and when to apply it?

Direct shear is the most widely used test for characterising shear strength in granular and cohesive-frictional soils: sands, silts and clays without fines. It is fast (1-3 days) and economical, but imposes the failure plane and does not measure pore pressures, which limits its accuracy in saturated clays (where triaxial CU with u measurements is preferred). It is used for foundation design, retaining walls, slopes and fills. In rocks it is applied to contacts and discontinuities (barrera-barrera Roger Hoek 1977, ISRM).

Applied formulas

Mohr-Coulomb criterion:

τ = c + σn · tan φ

Linear regression of n points:

tan φ = [n·Σ(σn·τ) − Σσn·Στ] / [n·Σσn² − (Σσn)²]

c = (Στ − tan φ · Σσn) / n

Coefficient of determination R²:

R² = 1 − SSres/SStot, where SSres = Σ(τobs − τpred)²

Residual parameters: cr ≈ 0 (cohesion is lost after rupture); φr is obtained from the descending branch or a large displacement test (reverse direct shear)

Acceptance criteria BS 1377-7 + BS EN ISO 17892-10: 3-4 points with σn covering the project range; shear rate 0.1-1 mm/min (drained); R² > 0.95

Calculate online

Enter 3 pairs (σn, τ) and obtain c and φ by Mohr-Coulomb linear regression.

Least-squares regression with 3 points. If c is slightly negative it is reported as 0 (sand with no real cohesion).

Calculation example

Input data — direct shear on silty sand SM, embankment Los Angeles
σn (kPa)τpeak (kPa)τresidual (kPa)
504632
1007661
200138121
300198181

Calculation for peak envelope with 4 points: Σσn = 650, Στ = 458, Σσn² = 140,000, Σ(σn·τ) = 100,600. tan φ = (4·100,600 − 650·458)/(4·140,000 − 650²) = (402,400 − 297,700)/(560,000 − 422,500) = 104,700/137,500 = 0.7614. φ = arctan 0.7614 = 37.3°. c = (458 − 0.7614·650)/4 = (458 − 495)/4 = −9.25 kPa. Since c is negative (small), it is interpreted as sand with no real cohesion and reported as c = 0, φ = 37.3° (standard practice BS 1377-7 + BS EN ISO 17892-10). Residual envelope: Σσn = 650, Στr = 395, Σσn·τr = 87,350. tan φr = (4·87,350 − 650·395)/137,500 = (349,400 − 256,750)/137,500 = 92,650/137,500 = 0.6738. φr = 33.9°, cr ≈ 0. R² peak = 0.999 (very good). Loss due to rupture: Δφ = 37.3 − 33.9 = 3.4°, typical behaviour of dense silty sand.

Result: Peak: c = 0, φ = 37.3° · Residual: cr = 0, φr = 33.9° · R² = 0.999.

Interpretation of results

The peak parameters (c = 0, φ = 37.3°) correspond to a dense silty sand in undisturbed state and are suitable for new foundation design on virgin ground. The residual parameters (φ = 33.9°) apply to slopes with a history of movement, reconsolidating compacted fills, or post-failure analysis. A peak-residual difference of 3° is moderate; in sensitive clays or loessial soils the difference can exceed 20° and long-term stability requires residual parameters mandatorily.

Reference standards

Frequently asked questions

When do I use peak and when residual?

Peak: design of new structures, foundations, slopes excavated in virgin ground. Residual: analysis of slopes with prior sliding (reactivation), dams with detected stability problems, back-analysis of failures. If in doubt, use residual (conservative).

Why direct shear vs triaxial?

Direct shear is fast and cheap but imposes the failure plane and does not measure u. Triaxial CU in saturated clay measures u and allows obtaining effective c' and φ' separated from total ones. In clean sands both give similar results; in clays triaxial is more accurate.

What shear rate do I use?

For sands 0.5-1.0 mm/min. For silts 0.1-0.3 mm/min. For clays 0.005-0.05 mm/min (fully drained). BS 1377-7 + BS EN ISO 17892-10 specifies t50 from oedometer × 20-50 to estimate minimum rate. Very high rate underestimates c in clays due to u generation without dissipation.

Square or circular box?

Square is the standard BS 1377-7 + BS EN ISO 17892-10 (60×60 mm or 100×100 mm). Circular (63.5 mm) used in old equipment; same area is assumed. For samples with coarse particles a 100×100 mm box is used to minimise size effect. Never particles > 1/10 of box side.

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